Use derivatives, integrals, optimization, and units in modeling contexts.
Applied calculus problems are translation problems. The hard part is often not computing a derivative or integral. The hard part is deciding what the words mean mathematically.
This lesson shows how to choose the right calculus tool and how to write a full solution with units and interpretation.
Learning objectives
After this lesson you should be able to:
choose derivatives for local rate problems;
choose integrals for accumulation problems;
choose optimization workflows for best-value problems;
use units to check setup;
connect position, velocity, and acceleration;
interpret marginal cost, revenue, and profit;
solve simple related-rates problems;
use SymPy and edumath helpers to check applied calculations.
Application problem roadmap
Read the question. Underline the requested quantity.
Identify units. Units often reveal the correct operation.
Choose the tool. Derivative, integral, optimization, limit, or related rates.
Define variables. State what each variable means and its units.
Set up equations. Translate words into formulas.
Solve step by step. Use calculus only after the setup is clear.
Check reasonableness. Units, sign, size, and context should make sense.
Interpret. Answer the original question in a sentence.
Tool selection guide
Wording in the problem
Meaning
Tool
instantaneous, marginal, slope, velocity
local rate
derivative
total, accumulated, area, amount added
accumulation
integral
maximum, minimum, largest, smallest, best
compare candidates
optimization
approaches, near, as input tends to
nearby behavior
limit
how fast one quantity changes when another changes
The integral of speed, \(|v(t)|\), gives total distance.
Walkthrough: velocity from position
A particle has position
\[
s(t)=t^2+3t
\]
meters at time \(t\) seconds. Find its velocity at \(t=2\).
Read the question. It asks for velocity at one instant.
Choose the tool. Velocity is derivative of position.
Differentiate.\[
v(t)=s'(t)=2t+3.
\]
Evaluate at \(t=2\).\[
v(2)=2(2)+3=7.
\]
Interpret. At 2 seconds, the particle is moving at 7 meters per second.
Walkthrough: displacement from velocity
Velocity is \(v(t)=3t^2\) meters per second. Find displacement from \(t=0\) to \(t=2\).
Read the question. It asks for accumulated position change.
Choose the tool. Accumulated change from a rate uses an integral.
Set up.\[
\int_0^2 3t^2\,dt.
\]
Find antiderivative.\[
\int 3t^2\,dt=t^3.
\]
Evaluate.\[
t^3\Big|_0^2=8-0=8.
\]
Interpret. The displacement is 8 meters.
Marginal analysis
In economics and business contexts, “marginal” usually means derivative.
Marginal cost: derivative of cost.
Marginal revenue: derivative of revenue.
Marginal profit: derivative of profit.
Walkthrough: marginal cost
Suppose
\[
C(x)=100+5x+0.2x^2
\]
is cost in dollars to produce \(x\) items. Find and interpret marginal cost at \(x=10\).
Read the question. Marginal cost means local rate of change of cost.
Choose the tool. Use a derivative.
Differentiate.\[
C'(x)=5+0.4x.
\]
Evaluate.\[
C'(10)=5+0.4(10)=9.
\]
Units. Dollars per item.
Interpret. Near 10 items, producing one more item increases cost by about 9 dollars.
Accumulation from rates
If a rate is measured in units per input, an integral over the input interval returns accumulated units.
Walkthrough: water flow
Water flows into a tank at rate
\[
r(t)=2t+1
\]
liters per minute. How much water enters from \(t=0\) to \(t=3\)?
Identify rate and interval. Rate is liters/minute, interval is minutes 0 to 3.
Choose the tool. Total amount from a rate uses an integral.
Set up.\[
\int_0^3(2t+1)\,dt.
\]
Find antiderivative.\[
t^2+t.
\]
Evaluate.\[
(3^2+3)-(0^2+0)=12.
\]
Interpret. The tank receives 12 liters of water.
Related rates introduction
Related rates problems involve quantities connected by an equation while they change with time.
Related-rates workflow
Draw or describe the situation.
Define variables as functions of time.
Write an equation connecting the variables.
Differentiate both sides with respect to time.
Substitute known values after differentiating.
Solve for the requested rate.
Walkthrough: growing square
A square has side length \(s\) centimeters. Its side length grows at \(ds/dt=3\) cm/s. How fast is area changing when \(s=5\) cm?
Equation. Area is \[
A=s^2.
\]
Differentiate with respect to time.\[
\frac{dA}{dt}=2s\frac{ds}{dt}.
\]
Substitute after differentiating.\[
\frac{dA}{dt}=2(5)(3)=30.
\]
Interpret. The area is increasing at 30 square centimeters per second.
WarningRelated-rates mistake
Do not substitute the side length before differentiating. If you replace \(s\) by 5 too early, the equation becomes \(A=25\), whose derivative incorrectly suggests no change.
Optimization applications
Applied optimization combines modeling with the optimization workflow.
Walkthrough: maximum revenue
Revenue is modeled by
\[
R(x)=-x^2+10x,
\]
where \(x\) is the number of units sold. Find the production level that maximizes revenue.
Read the question. It asks for a maximum.
Choose the tool. Use optimization with derivatives.
Classify. Since \(R''(x)=-2<0\), the graph is concave down, so this is a maximum.
Interpret. The revenue is maximized at 5 units in this model.
Probability density preview
If \(f(x)\) is a probability density, probability over an interval is area:
\[
P(a\le X\le b)=\int_a^b f(x)\,dx.
\]
This is why integrals are central in probability and statistics. The units work because density has units of probability per input unit, and integration returns probability.
Common mistakes and repairs
Mistake: using a derivative for a total
Repair: if the question asks for total amount, accumulated change, or area, use an integral.
Mistake: using an integral for an instantaneous rate
Repair: if the question says instantaneous, marginal, or “at time t=a,” use a derivative.
Mistake: ignoring units
Repair: write units after every major result. Units often reveal whether the setup is wrong.
Mixed practice
Marginal cost is a derivative or an integral?
Total distance from velocity uses a derivative or an integral?
Maximum profit usually requires which calculus workflow first?
If position is meters and time is seconds, what are velocity units?
If a rate is liters per minute, what are the units of its integral over minutes?
Given \(s(t)=t^3\), find velocity at \(t=2\).
Given \(v(t)=4t\), find displacement on \([0,3]\).
If \(A=s^2\) and \(ds/dt=2\), find \(dA/dt\) when \(s=6\).
TipSolutions
Derivative.
Integral of speed. Integral of velocity gives displacement.